# NCERT Solutions for Class 9 Maths Chapter 12 Heron’s Formula

NCERT Solutions for Class 9 Maths Chapter 12 Heron’s Formula Exercise 12.1 and Exercise 12.2 available to download in PDF file. Get English Medium solutions of these exercises to study online. We have NCERT solutions for class 9 in Hindi Medium and English Medium. Students will get benefit of the solutions. They can solve every problem of this chapter. Get the solutions below.

## NCERT Solutions for Class 9 Maths Chapter 12 Heron’s Formula

Class 9 Maths Chapter 12 solutions has two exercises for practice. The chapter is related to Heron’s Formula. NCERT 9 Maths Chapter 12 Heron’s Formula Solutions Hindi and English Medium.

Class 9 Maths Chapter 12 Exercise 12.1 Solutions
Exercise 12.1 Solutions Online
प्रश्नावली 12.1 हल in Hindi

Class 9 Maths Chapter 12 Exercise 12.2 Solutions
Exercise 12.2 Solutions Online
प्रश्नावली 12.2 हल in Hindi

#### Introduction – Heron’s Formula

You have studied in earlier classes about figures of different shapes such as squares, rectangles, triangles and quadrilaterals. You have also calculated perimeters and the areas of some of these figures like rectangle, square etc. For instance, you can find the area and the perimeter of the floor of your classroom.

Let us take a walk around the floor along its sides once; the distance we walk is its perimeter. The size of the floor of the room is its area.

So, if your classroom is rectangular with length 10 m and width 8 m, its perimeter would be 2(10 m + 8 m) = 36 m and its area would be 10 m × 8 m, i.e., 80 m2.

Unit of measurement for length or breadth is taken as metre (m) or centimetre (cm) etc.
Unit of measurement for area of any plane figure is taken as square metre (m2) or square centimetre (cm2) etc.

Suppose that you are sitting in a triangular garden. How would you find its area? From Chapter 9 and from your earlier classes, you know that:

Area of a triangle = ½ × base × height