NCERT Solutions for Class 10 Maths Chapter 11 Constructions Exercise 11.1 and Exercise 11.2 available in PDF file to free download. Download updated CBSE syllabus CBSE NCERT Solutions for all classes. NCERT Books for class 10 can be downloaded in Hindi & English Medium.

## NCERT Solutions for Class 10 Maths Chapter 11 All Exercises

There are only two exercises in this chapter. Students will learn about constructions. In Class IX, you have done certain constructions using a straight edge (ruler) and a compass, e.g., bisecting an angle, drawing the perpendicular bisector of a line segment, some constructions of triangles etc. and also gave their justifications. In this chapter, we shall study some more constructions by using the knowledge of the earlier constructions. You would also be expected to give the mathematical reasoning behind why such constructions work.

### Solutions of Class 10 Maths Constructions English Medium

**NCERT 10 Maths Chapter 11 Exercise 11.1 Solutions**

Read or view online Exercise 11.1 Solutions

Download Exercise 11.1 in English PDF

**10 Maths Chapter 10 Exercise 11.2 Solutions**

Read or view online Exercise 11.2

Download Exercise 11.2 in English PDF

### Hindi Medium Solutions Chapter 11

प्रश्नावली 10.2 Solutions in Hindi

प्रश्नावली 10.2 Solutions in Hindi

**Division of a Line Segment**

Suppose a line segment is given and you have to divide it in a given ratio, say 3 : 2. You may do it by measuring the length and then marking a point on it that divides it in the given ratio. Class 10 Maths Chapter 11 Constructions.

**Construction of Tangents to a Circle**

You have already studied in the previous chapter that if a point lies inside a circle, there cannot be a tangent to the circle through this point. However, if a point lies on the circle, then there is only one tangent to the circle at this point and it is perpendicular to the radius through this point. Therefore, if you want to draw a tangent at a point of a circle, simply draw the radius through this point and draw a line perpendicular to this radius through this point and this will be the required tangent at the point. You have also seen that if the point lies outside the circle, there will be two tangents to the circle from this point.

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